Mathematica: v13.2+: Division of one temperature by another will result in a numeric ratio given by the value of both temperatures in Kelvin. Source Wolfram Language (Mathematica) online help reference

Mathematica: v13.2+: Division by temperature units will produce a quantity equivalent to the temperature converted to Kelvin before division, with results canonically given in Kelvin. Source Wolfram Language (Mathematica) online help reference

GOTCHA: Mathematica v13.2+: Operations on "DegreesFahrenheit" °F and "DegreesCelsius" °C are now performed using Kelvins (K). CASE: Naive percentage operation gives answer relative to Kelvins. Use "DegreesCelsiusDifference"/"DegreesFahrenheitDifference"!

Example 11: Total (qDotTot), sensible (qDotSen), and latent cooling (qDotLat) required for cooling air Gallery Tutorial TRAIL: Air Conditioning Psychrometrics (vs CED Engineering course): Example results (only) in Mathematica and SysML using the Webel Psy package and MPsy class Section Slide kind plot table

Example 10: Condition and dehumidify air by chilling and condensing some moisture: Process table Gallery Tutorial TRAIL: Air Conditioning Psychrometrics (vs CED Engineering course): Example results (only) in Mathematica and SysML using the Webel Psy package and MPsy class Section Slide kind plot table

Example 09: Moisture added to air: Amount (mass) Gallery Tutorial TRAIL: Air Conditioning Psychrometrics (vs CED Engineering course): Example results (only) in Mathematica and SysML using the Webel Psy package and MPsy class Section Slide kind plot table

Example 08b: Humidification: As a 2-step (3-state) process Gallery Tutorial TRAIL: Air Conditioning Psychrometrics (vs CED Engineering course): Example results (only) in Mathematica and SysML using the Webel Psy package and MPsy class Section Slide kind plot table

Example 08a: Humidification: Drying lumber with air: required volumetric air flow rate Gallery Tutorial TRAIL: Air Conditioning Psychrometrics (vs CED Engineering course): Example results (only) in Mathematica and SysML using the Webel Psy package and MPsy class Section Slide kind plot table

Example 07: Sensible cooling: 'qDotSen' (-ve): energy transfer rate FROM humid air Gallery Tutorial TRAIL: Air Conditioning Psychrometrics (vs CED Engineering course): Example results (only) in Mathematica and SysML using the Webel Psy package and MPsy class Section Slide kind plot table

Example 06: Sensible heating: 'qSen' per mass (+ve): energy transfer TO humid air Gallery Tutorial TRAIL: Air Conditioning Psychrometrics (vs CED Engineering course): Example results (only) in Mathematica and SysML using the Webel Psy package and MPsy class Section Slide kind plot table

Example 05: Sensible heating: 'qSen' (+ve): energy transfer TO humid air Gallery Tutorial TRAIL: Air Conditioning Psychrometrics (vs CED Engineering course): Example results (only) in Mathematica and SysML using the Webel Psy package and MPsy class Section Slide kind plot table

Example 04: Values from dry bulb temperature 'tdb' and wet bulb temperature 'twb' Gallery Tutorial TRAIL: Air Conditioning Psychrometrics (vs CED Engineering course): Example results (only) in Mathematica and SysML using the Webel Psy package and MPsy class Section Slide kind plot table

Example 03b: Values from dry bulb temperature 'tdb' and wet bulb temperature 'twb' Gallery Tutorial TRAIL: Air Conditioning Psychrometrics (vs CED Engineering course): Example results (only) in Mathematica and SysML using the Webel Psy package and MPsy class Section Slide kind plot table

Example 03a: Values from dry bulb temperature 'tdb' and wet bulb temperature 'twb' Gallery Tutorial TRAIL: Air Conditioning Psychrometrics (vs CED Engineering course): Example results (only) in Mathematica and SysML using the Webel Psy package and MPsy class Section Slide kind plot table

Example 02: Values from dry bulb temperature 'tdb' and wet bulb temperature 'twb' (sling psychrometer) Gallery Tutorial TRAIL: Air Conditioning Psychrometrics (vs CED Engineering course): Example results (only) in Mathematica and SysML using the Webel Psy package and MPsy class Section Slide kind plot table

Example 01: Values from 'tdb' and relative humidity 'r' Gallery Tutorial TRAIL: Air Conditioning Psychrometrics (vs CED Engineering course): Example results (only) in Mathematica and SysML using the Webel Psy package and MPsy class Section Slide kind plot table

When calibrated to ITS-90, where one must interpolate between the defining points of gallium and indium, the boiling point of VSMOW water is about 10 mK less, about 99.974 °C. Source Wikipedia

Precise measurements show that the boiling point of VSMOW water under one standard atmosphere of pressure is actually 373.1339 K (99.9839 °C) when adhering strictly to the two-point definition of thermodynamic temperature. Source Wikipedia

Fun fact: The normal boiling point of water isn't exactly 100 °C (at least not since 2019 when the definition of the Kelvin scale was changed to use the Boltzmann constant and decoupled from the triple point of water)

Webel vs SysPhS-1.1: Annex A.5: Humidifier: The water temperature from TemperatureIncreaseConstraint and HeatingCalculationConstraint starts at 0 °C (should probably be the environment temperature 20 °C). Needs an additional parameter and initial value.

The volumetric heat capacity can also be expressed as the specific heat capacity (heat capacity per unit of mass, in J/K/kg) times the density of the substance (in kg/L, or g/mL). Source Wikipedia

The SI unit of volumetric heat capacity is joule per kelvin per cubic meter, J/K/m3 or J/(K·m3). Source Wikipedia

Informally, it is the amount of energy that must be added, in the form of heat, to one unit of volume of the material in order to cause an increase of one unit in its temperature. Source Wikipedia

The volumetric heat capacity of a material is the heat capacity of a sample of the substance divided by the volume of the sample. Source Wikipedia

Isobaric volumetric heat capacity C(P,v) J⋅cm−3⋅K−1 of liquid Water at 100 °C = 4.2160 Source Wikipedia

Isobaric volumetric heat capacity C(P,v) J⋅cm−3⋅K−1 of liquid Water at 25 °C = 4.1796 Source Wikipedia